18x^2+12x=360x+72

Solution for 18x^2+12x=360x+72 equation:

18x^2+12x=360x+72

We move all terms to the left:

18x^2+12x-(360x+72)=0

We get rid of parentheses

18x^2+12x-360x-72=0

We add all the numbers together, and all the variables

18x^2-348x-72=0

a = 18; b = -348; c = -72;
Δ = b2-4ac
Δ = -3482-4·18·(-72)
Δ = 126288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{126288}=\sqrt{144*877}=\sqrt{144}*\sqrt{877}=12\sqrt{877}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-348)-12\sqrt{877}}{2*18}=\frac{348-12\sqrt{877}}{36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-348)+12\sqrt{877}}{2*18}=\frac{348+12\sqrt{877}}{36}
$